Time and Distance Aptitude Questions and Answers
This section focuses on "Time and Distance" in Quantitative Aptitude. These Multiple Choice Questions (mcq) should be practiced to improve the Quantitative Aptitude skills required for various interviews (campus interviews, walk-in interviews, company interviews), placements, entrance exams and other competitive examinations.
1. A person crosses a 300 m long road in 10 minutes. What is his speed in km per hour?
Explanation: Speed = (300)/(10*60)m/sec = 0.5m/s.
Converting m/sec to km/hr = (0.5*18)/5 => 1.8 km/hr.
2. Excluding stoppages, the speed of a bus is 36 kmph and including stoppages, it is 27 kmph. For how many minutes does the bus stop per hour?
Explanation: Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = (9/36) x 60min => 15 min.
3. The ratio between the speeds of two trains is 3 : 6. If the second train runs 300 km in 6 hours, then the speed of the first train is:
Explanation: Let the speed of two trains be 3x and 5x km/hr.
5x = 300/6 => x= 10
Speed of first train = (3 x 10) km/hr = 30 km/hr.
4. Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 20 kmph, he will reach there at 12 noon if he travels at 30 kmph. At what speed must he travel to reach A at 1 P.M.?
Explanation: Let the distance travelled by x km.
Then, (x/20) - (x/30) = 2
3x - 2x = 120 => x = 120 km.
Time taken to travel 120 km at 20 km/hr = 6hrs
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M
Required speed = (120/10)kmph => 12 kmph
5. The speed of a van increases by 10 kmph after every one hour. If the distance travelled in the first one hour
was 60 km, what was the total distance travelled in 6 hours?
Explanation: Distance travelled in 1ST hour =60 km
distance travelled in 2nd hour =70 km
Total distance travelled = 6/2(2*60+(6-1)10) => 510km
6. Devki rides his scooter 10km at an average speed of 10 km/hr and again travels 30km at an average speed
of 15 km/hr. What is her average speed for the entire trip approximately?
Explanation: Total distance travelled
Time taken to travel 10 km at an average speed of 10 km/hr =10/10=1 Hr
Time taken to travel 30 km at an average speed of 15 km/hr =30/15=2 Hr
Total time taken = 1+2 => 3hr
Average speed =Total distance travelled /Total time taken
=40/3 => 13.33 Km/Hr
7. A monkey takes 20 jumps for every 30 jumps of a dog but 10 jumps of a monkey are equal to 15 jumps of
the dog. Compare their speeds.
Explanation: 10 x = 15y
x = (15/10) y ----> eq 1
20x=30y -------> eq 2
put eq 1 in eq 2
30y=30y => 1:1
8. Raghu starts a bike at 20 km/hr and he increases his speed in every hour by 5 km/hr. Then the maximum
distance covered by him in 10 hours is:
Explanation: Speed of the rider = 20km/hr.
Distance covered in 1st hour = 20 km.
He increased his speed in every 1 hour by 5 km/hr.
Distance covered in every 1 hours will be, 25, 30, ,... upto 10 terms.(for 10 hours).
The above series is an A.P series;
Sum of first n terms = (n/2)(2a+(n-1)d)
Here, a = 20, d = 5 and n = 10.
Sum of first 10 terms = (10/2)(2(20)+(9)5) = 425
Hence, he covers 425 km in 10 hours.
9. In covering a definite distance, the speeds of P & Q are in the ratio of 5:6. P takes 45 mins more than Q to
reach the target. The time taken by P to reach the target is.
Explanation: Ratio of speeds = 5:6
Ratio of time =6:5
Suppose P takes 6x hrs and Q takes 5x hrs to reach the target.
Then, 6x – 5x = 45/60
Time taken by P = 6x hrs
i.e., the time taken by P to reach the target is 4hrs 30mins
10. P is thrice as fast as Q and Q is 4 times as fast as R. If the journey covered by R is 48 mins, then the time
to be covered by Q.
Explanation: Let R’s speed = x km/hr
Then Q’s speed = 4x km/hr
P’s speed = 12x km/hr
Ratio of speeds of P =12:4:1
Ratio of time taken = 1/12: ¼:1
If R takes 12 mins, then Q takes 3 mins
If R takes 48 mins, then
Q takes =(3/12 *48)mins