Time and Distance Aptitude Questions and Answers
This section focuses on "Time and Distance" in Quantitative Aptitude. These Multiple Choice Questions (mcq) should be practiced to improve the Quantitative Aptitude skills required for various interviews (campus interviews, walk-in interviews, company interviews), placements, entrance exams and other competitive examinations.
1. A person crosses a 300 m long road in 10 minutes. What is his speed in km per hour?
Explanation: Speed = (300)/(10*60)m/sec = 0.5m/s.
Converting m/sec to km/hr = (0.5*18)/5 => 1.8 km/hr.
2. If a man walks at 20 km/hr instead of 10 km/hr, he would have walked 10 km more. The actual distance travelled by him is:
Explanation: Let the actual distance travelled be x km.
Then, x/10 = (x + 10)/20
20x = 10x + 100 => 10x = 100 => x = 10 km.
3. Excluding stoppages, the speed of a bus is 36 kmph and including stoppages, it is 27 kmph. For how many minutes does the bus stop per hour?
Explanation: Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = (9/36) x 60min => 15 min.
4. A man on tour travels first 320 km at 32 km/hr and the next 320 km at 160 km/hr. The average speed for the first 640 km of the tour is:
Explanation: Total time taken = ((320/32) + (320/160)) => 12 hrs
Average speed = 720/12 => 60 km/hr
5. The ratio between the speeds of two trains is 3 : 6. If the second train runs 300 km in 6 hours, then the speed of the first train is:
Explanation: Let the speed of two trains be 3x and 5x km/hr.
5x = 300/6 => x= 10
Speed of first train = (3 x 10) km/hr = 30 km/hr.
6. In covering a distance of 60 km, Prateek takes 4 hours more than Divesh. If Prateek doubles his speed, then he would take 2 hour less than Divesh. Prateek speed is:
Explanation: Let Prateek speed be x km/hr.
Then, (60/2x) - (60/4x) = 6
24x = 60 => x = 2.5 km/hr.
7. Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 20 kmph, he will reach there at 12 noon if he travels at 30 kmph. At what speed must he travel to reach A at 1 P.M.?
Explanation: Let the distance travelled by x km.
Then, (x/20) - (x/30) = 2
3x - 2x = 120 => x = 120 km.
Time taken to travel 120 km at 20 km/hr = 6hrs
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M
Required speed = (120/10)kmph => 12 kmph
8. kajal rides his scooter 32km at an average speed of 8 km/hr and again travels 24km at an average speed of 12 km/hr. What is her average speed for the entire trip approximately?
Explanation: Total time taken = ((32/8) + (24/12)) => 6hrs
Average speed =Total distance travelled /Total time taken => 56/6 => 9.33kmph
9. The speed of a van increases by 10 kmph after every one hour. If the distance travelled in the first one hour
was 60 km, what was the total distance travelled in 6 hours?
Explanation: Distance travelled in 1ST hour =60 km
distance travelled in 2nd hour =70 km
Total distance travelled = 6/2(2*60+(6-1)10) => 510km
10. A car covers a distance of 2km in 1 minute whereas a bus covers a distance of 10 kms in 10
minutes. What is the ratio of their speed?
Explanation: Speed of the Car = 2km/min
Speed of the bus= 10km/10min => 1km/min
Speed of the car : Speed of the bus => 2 : 1
11. Devki rides his scooter 10km at an average speed of 10 km/hr and again travels 30km at an average speed
of 15 km/hr. What is her average speed for the entire trip approximately?
Explanation: Total distance travelled
Time taken to travel 10 km at an average speed of 10 km/hr =10/10=1 Hr
Time taken to travel 30 km at an average speed of 15 km/hr =30/15=2 Hr
Total time taken = 1+2 => 3hr
Average speed =Total distance travelled /Total time taken
=40/3 => 13.33 Km/Hr
12. Siva leaves chennai at 3 am and reaches Hyderabad at 11 am . Anirudh leaves Hyderabad at 5 am
and reaches chennai at 12:00 noon. At what time do they cross each other?
Explanation: Time taken by Siva = 8 h
Time taken by Anirudh = 7 h
For your convenience take the product of times taken by both as a distance.
Then the distance = 56km
Since, Siva covers half of the distance in 2 hours(i.e at 5 am)
Now, the rest half (i.e 28 km) will be coverd by both Anirudh and Siva
Time taken by them = 28/15 = 1 hr 52 min
Thus , they will cross each other at 6 : 52am.
13. A monkey takes 20 jumps for every 30 jumps of a dog but 10 jumps of a monkey are equal to 15 jumps of
the dog. Compare their speeds.
Explanation: 10 x = 15y
x = (15/10) y ----> eq 1
20x=30y -------> eq 2
put eq 1 in eq 2
30y=30y => 1:1
14. Karthiga drive a speed of 27 km/hr at a distance of 54 km. At what speed would she need to drive during the
next 3 hrs to have an average of 54km/hr for the entire driving session.
Explanation: Let the speed of driving be x km/hr
Total time taken = (54/27 hrs + 3 hrs)
=(2 hrs + 3 hrs)
Total distance covered = (54+3 x) km
Therefore (54 +3x) / 5= 54
54+3x = 270
So driving speed is x = 72 km/hr
15. Raghu starts a bike at 20 km/hr and he increases his speed in every hour by 5 km/hr. Then the maximum
distance covered by him in 10 hours is:
Explanation: Speed of the rider = 20km/hr.
Distance covered in 1st hour = 20 km.
He increased his speed in every 1 hour by 5 km/hr.
Distance covered in every 1 hours will be, 25, 30, ,... upto 10 terms.(for 10 hours).
The above series is an A.P series;
Sum of first n terms = (n/2)(2a+(n-1)d)
Here, a = 20, d = 5 and n = 10.
Sum of first 10 terms = (10/2)(2(20)+(9)5) = 425
Hence, he covers 425 km in 10 hours.
16. I reach the bus stop 15 min late if I walk at 2 kmph Starting from my office . Instead, if I walk at 3 kmph, I
reach the bus stop 10 min early. How far is bus stop from my office?
Explanation: Let the distance between the office and the bus stop be 1 km
Time required at 2 kmph
= 1/2 = 30 mins
Time required at 3 kmph
= 1/3 = 20 mins
Difference = 30−20=10 min.
Actual difference in timings = 15+10 =25 min
If difference is 10 min, distance is 1 km
⇒ If difference is 25 min, distance is 2.5 km
Hence the required answer is 2.5 km
17. In covering a definite distance, the speeds of P & Q are in the ratio of 5:6. P takes 45 mins more than Q to
reach the target. The time taken by P to reach the target is.
Explanation: Ratio of speeds = 5:6
Ratio of time =6:5
Suppose P takes 6x hrs and Q takes 5x hrs to reach the target.
Then, 6x – 5x = 45/60
Time taken by P = 6x hrs
i.e., the time taken by P to reach the target is 4hrs 30mins
18. Arun steals a van at 8.30 am and drives it at 40km/hr. The theft is discovered at 9 a.m and the owner
sets off in another van at 55km/hr. when will he overtake arun?
Explanation: Suppose the arin is overtaken x hrs after 8.30 a.m
Then distance covered by arun in x hrs = distance covered by the owner in(x-1/2) hrs
40x = 55x -55/2
55x – 40x =55/2
X = 55/2*1/15
x= 1hr 50mins
so the thief is overtaken at 10.20 a.m
19. P is thrice as fast as Q and Q is 4 times as fast as R. If the journey covered by R is 48 mins, then the time
to be covered by Q.
Explanation: Let R’s speed = x km/hr
Then Q’s speed = 4x km/hr
P’s speed = 12x km/hr
Ratio of speeds of P =12:4:1
Ratio of time taken = 1/12: ¼:1
If R takes 12 mins, then Q takes 3 mins
If R takes 48 mins, then
Q takes =(3/12 *48)mins
20. A bike starts with a speed of 60 km/hr at 8a.m. Due to the problem in engine it reduces its speed as 20
km/hr for every 1 hour. After 9 am, the time taken to covers 15 km is:
Explanation: Initial speed of the bike= 60 km/hr
Due to engine problem, speed is reduced to 20km for every 1 hour
Speed of the car at 9 am = (60 - 20) = 40km/hr
Time to cover 15 km at 40 km/hr = distance/speed
= 15/40 hours. = 3/8 hours
= 3/8 x 60 minutes = 45/2 minutes = 22 minutes + 1/2 minutes
= 22 minutes + 1/2 x 60 seconds
= 22 minutes and 30 seconds.