Percentage Aptitude Questions and Answers
This section focuses on "Percentage" of Quantitative Aptitude. These Multiple Choice Questions (mcq) should be practiced to improve the Quantitative Aptitude skills required for various interviews (campus interviews, walk-in interviews, company interviews), placements, entrance exams and other competitive examinations.
1. In final exam of class X there are 150 students 10% students failed. How many students passed to class
XI?
A. 120
B. 135
C. 130
D. 140
View Answer
Ans : B
Explanation: Percentage of students passed to class XI = (100 % - 10 %) of 150
= 90 % of 150
=> 90/100 × 150
=> 135
Therefore, 135 students passed to class XI
2. Rahul gets 75% marks in examinations. If these are 600 marks, find the maximum marks.
A. 800
B. 900
C. 1000
D. 1200
View Answer
Ans : A
Explanation: Let the maximum marks be x
Then 75 % of x = 600
75/100 × x = 600
x = (600 × 100)/75
s = 800
Therefore, maximum marks in the examinations are 800.
3. In a college of 1250 students, 56 % are boys. Find the number of girls and number of boys in the college?
A. 500
B. 550
C. 600
D. 650
View Answer
Ans : B
Explanation: Number of boys in the college = 56 % of 1250
= 56/100 × 1250
= 700
Number of girls in the college = Total number of students in the college - Number of boys
= 1250 – 700
= 550
4. A cricket team lost 60% of the matches it played. If it won 40 matches, find the number of matches it
played.
A. 80
B. 90
C. 100
D. 120
View Answer
Ans : C
Explanation: Percentage of matches lost = 60%
Therefore Percentage of matches won (100 - 60) % = 40%
Let the number of matches played be x.
Then 40 % of x = 40
40/100 × x =40
x = (40 × 100)/40
x = (4000)/40
x = 100
Therefore, the total number of matches played is 100
5. An alloy contains 40 % of bronze. What quantity of alloy is required to get 350 g of bronze?
A. 875g
B. 900g
C. 850g
D. 825g
View Answer
Ans : A
Explanation: Let the quantity of alloy required = x g
Then 40 % of x =350 g
⇒ 40/100 × x = 350 g
x = 875 g
6. In a basket of eggs, 25% of them are rotten and 30 are in good condition. Find the total number of eggs in
the basket.
A. 35
B. 40
C. 45
D. 50
View Answer
Ans : B
Explanation: Let the total number of eggs in the basket be x
25 % of the eggs are rotten, and eggs in good condition are 30
Therefore, according to the question,
75% of x = 30
75/100 × x = 30
x = (30 × 100)/75
x = 40
Therefore, total number of eggs in the basket is 40
7. Gugan obtained a total of 875 marks out of 1300 in an examination. What is his approximate
percentage in the examination?
A. 67
B. 67.1
C. 67.2
D. 67.3
View Answer
Ans : D
Explanation: Required percentage = (875/ 1300) × 100
=67.3
8. One fifth of third of half of a number is 50.What will be 20% of that number?
A. 250
B. 300
C. 350
D. 400
View Answer
Ans : B
Explanation: (1/5) ×(1/3)×(1/2)× x = 50
x/30 =50
x = 50*30
x = 1500
20 % of 1500
= 300
9. A mixture of 60 kg of rice and dhal contains 60% of dhal. The new mixture is formed by adding 15 kg of
dhal. What is the percentage of rice in the new mixture?
A. 30%
B. 31%
C. 32%
D. 33%
View Answer
Ans : C
Explanation: 60 kg = 36 kg dhal 24 kg rice
-------- 15 kg dhal
Total = 15 kg dhal 24 kg rice (new)
24/75×100=32%
10. Two employees A and B are paid a total of Rs. 5000 per week by their employer. If A is paid 150 percent
of the sum paid to B, how much is B paid per week?
A. 1900
B. 2000
C. 2050
D. 2100
View Answer
Ans : B
Explanation: Let the amount paid to A per week = x
and the amount paid to B per week = y
Then x + y = 5000
But x = 150% of y
= 150y/100
= 15y/10
∴15y/10 + y = 5000
⇒ y[15/10 + 1] = 5000
⇒ 25y = 50000
⇒ y = 50000/25
y = Rs.2000
11. From the salary of Kartik 20% is deducted as house rent, 10% he spends on children’s education and 10%
on watching movies. If his savings are Rs.10000/- then his total salary is:
A. 16000
B. 16500
C. 16666.67
D. 18000
View Answer
Ans : C
Explanation: spends = 40% remaining 60% = 10000
Total salary = 10000 × 100 / 60
= 1000000 / 60
= 16666.66
12. Forty percent of Mouli’s annual salary is equal to 160% of Surya’s annual salary. Surya’s monthly salary
is 80%of Gowthaman’s monthly salary. If Gowthaman’s annual salary is ` 12 lacs, what is Mouli’s monthly
salary ?
A. 180000
B. 120000
C. 320000
D. 250000
View Answer
Ans : C
Explanation: Gowthaman’s monthly salary = 12,00,000/12
= 1,00,000
Surya’s monthly salary = 1,00,000 x 80/100
= 80,000
Mouli’s monthly salary = 80,000x 1600/40
=3,20,000
13. Chenna dhal is now being sold at Rs. 60 a kg. Last month, is rate was Rs. 75 per kg. By how much
percent should a family reduce its consumption so as to keep the expenditure fixed?
A. 20%
B. 25%
C. 12.5%
D. 15%
View Answer
Ans : A
Explanation: Let a family's monthly consumption of chenna dhal be x kg.
To keep the expenditure fixed,
their consumption for this month should be 60x/75 = 4x/5.
Reduction in consumption = x/5 = 20% of x
14. A candidate scoring 50% in an examination fails by 60 marks , while another candidate scores 75 %
mark, gets 40 marks more than the minimum pass marks . Find the minimum pass mark.
A. 180
B. 200
C. 210
D. 220
View Answer
Ans : D
Explanation: Let x be the maximum marks,
Then (50% of x)+60 = (75% of x)-40
x/2 +60 = 3x/4 -20
60+20 = 3x/4 – x/ 2
X=320
Hence maximum marks = 320
Minimum pass marks = 320/2 + 60 = 220
15. In an exam Aashika secured 1350 marks. If she secured 35 % marks, find the maximum marks.
A. 3300
B. 3200
C. 3300
D. 3375
View Answer
Ans : D
Explanation: Let the maximum marks be x.
Aashika’s marks = 40% of x
Aashika secured 1350 marks
Therefore, 40% of x = 1350
⇒ 40/100 × x = 1350
x = (1350 × 100)/40
x =135000/40
x = 3375
16. Find the increase value if 450 is increased by 90 %.
A. 850
B. 855
C. 860
D. 865
View Answer
Ans : B
Explanation: Increase = 90 % of 450
= 90/100 × 450
= 40500/100
= 405
Therefore, increase value = 450 + 405 = 855
17. The population in a small town increases from 50000 to 63750 in one year. Find the percentage increase
in population.
A. 25%
B. 27%
C. 27.5%
D. 25.5%
View Answer
Ans : C
Explanation: Population in a small town last year = 50000
Population in a small town after one year = 63750
Increase in population = 63750 - 50000 = 13750
Therefore,
percentage increase in population = Increase in population/Last year population × 100 %
= 13750/50000 × 100
= 1375000/50000
= 27.5%
Thus, the increase in population is 27.5%
18. In an election between two candidates, one got 45% of the total valid votes, 40% of the votes were
invalid. If the total number of votes was 15000, the number of valid votes that the other candidate got, was .
A. 4900
B. 4950
C. 5000
D. 5050
View Answer
Ans : B
Explanation: Total number of votes = 15000
Given that 40% of Percentage votes were invalid
=> Valid votes = 60%
Total valid votes = 15000* 60/100
1st candidate got 45% of the total valid votes.
Hence the 2nd candidate should have got 55% of the total valid votes
=> Valid votes that 2nd candidate got = total valid votes x 55/100
=15000*60/100*55/100
=4950
19. In an election between two candidates, the winner secured 85% of the total votes cast and wins by a
majority of 6300 votes. How many votes did the losing candidate get?
A. 1350
B. 1400
C. 1450
D. 1500
View Answer
Ans : A
Explanation: Total votes cast = 100%
Winner gets = 85%
Loser gets = 100 – 85 = 15%
Majority = Votes secured by winner – Votes secured by loser
= 85% - 15%
=70% =6300
Votes by the losing candidate = x = 15%
x = (15 * 6300)/70
x =(94500/70)
x = 1350
20. In a college election between two candidates, one candidate got 25% of the total valid votes. 30% of the
votes were invalid. If the total votes were 7600, what is the number of valid votes the other candidate got ?
A. 3990
B. 4000
C. 4050
D. 4100
View Answer
Ans : A
Explanation: Total valid votes = 70% of 7600 = 5320
Number of valid votes to other candidate = 75% of 5320
= 75/100 *5320
= 399000/100
= 3990
Discussion