## Percentage Aptitude Questions and Answers

This section focuses on "Percentage" of Quantitative Aptitude. These Multiple Choice Questions (mcq) should be practiced to improve the Quantitative Aptitude skills required for various interviews (campus interviews, walk-in interviews, company interviews), placements, entrance exams and other competitive examinations.

1. In final exam of class X there are 150 students 10% students failed. How many students passed to class
XI?

A. 120

B. 135

C. 130

D. 140

View Answer

Ans : B

Explanation: Percentage of students passed to class XI = (100 % - 10 %) of 150

= 90 % of 150

=> 90/100 × 150

=> 135

Therefore, 135 students passed to class XI

2. In a college of 1250 students, 56 % are boys. Find the number of girls and number of boys in the college?

A. 500

B. 550

C. 600

D. 650

View Answer

Ans : B

Explanation: Number of boys in the college = 56 % of 1250

= 56/100 × 1250

= 700

Number of girls in the college = Total number of students in the college - Number of boys

= 1250 – 700

= 550

3. An alloy contains 40 % of bronze. What quantity of alloy is required to get 350 g of bronze?

A. 875g

B. 900g

C. 850g

D. 825g

View Answer

Ans : A

Explanation: Let the quantity of alloy required = x g

Then 40 % of x =350 g

⇒ 40/100 × x = 350 g

x = 875 g

4. Gugan obtained a total of 875 marks out of 1300 in an examination. What is his approximate
percentage in the examination?

A. 67

B. 67.1

C. 67.2

D. 67.3

View Answer

Ans : D

Explanation: Required percentage = (875/ 1300) × 100

=67.3

5. A mixture of 60 kg of rice and dhal contains 60% of dhal. The new mixture is formed by adding 15 kg of
dhal. What is the percentage of rice in the new mixture?

A. 30%

B. 31%

C. 32%

D. 33%

View Answer

Ans : C

Explanation: 60 kg = 36 kg dhal 24 kg rice

-------- 15 kg dhal

Total = 15 kg dhal 24 kg rice (new)

24/75×100=32%

6. From the salary of Kartik 20% is deducted as house rent, 10% he spends on children’s education and 10%
on watching movies. If his savings are Rs.10000/- then his total salary is:

A. 16000

B. 16500

C. 16666.67

D. 18000

View Answer

Ans : C

Explanation: spends = 40% remaining 60% = 10000

Total salary = 10000 × 100 / 60

= 1000000 / 60

= 16666.66

7. Chenna dhal is now being sold at Rs. 60 a kg. Last month, is rate was Rs. 75 per kg. By how much
percent should a family reduce its consumption so as to keep the expenditure fixed?

A. 20%

B. 25%

C. 12.5%

D. 15%

View Answer

Ans : A

Explanation: Let a family's monthly consumption of chenna dhal be x kg.

To keep the expenditure fixed,

their consumption for this month should be 60x/75 = 4x/5.

Reduction in consumption = x/5 = 20% of x

8. In an exam Aashika secured 1350 marks. If she secured 35 % marks, find the maximum marks.

A. 3300

B. 3200

C. 3300

D. 3375

View Answer

Ans : D

Explanation: Let the maximum marks be x.

Aashika’s marks = 40% of x

Aashika secured 1350 marks

Therefore, 40% of x = 1350

⇒ 40/100 × x = 1350

x = (1350 × 100)/40

x =135000/40

x = 3375

9. The population in a small town increases from 50000 to 63750 in one year. Find the percentage increase
in population.

A. 25%

B. 27%

C. 27.5%

D. 25.5%

View Answer

Ans : C

Explanation: Population in a small town last year = 50000

Population in a small town after one year = 63750

Increase in population = 63750 - 50000 = 13750

Therefore,

percentage increase in population = Increase in population/Last year population × 100 %
= 13750/50000 × 100

= 1375000/50000

= 27.5%

Thus, the increase in population is 27.5%

10. In an election between two candidates, the winner secured 85% of the total votes cast and wins by a
majority of 6300 votes. How many votes did the losing candidate get?

A. 1350

B. 1400

C. 1450

D. 1500

View Answer

Ans : A

Explanation: Total votes cast = 100%

Winner gets = 85%

Loser gets = 100 – 85 = 15%

Majority = Votes secured by winner – Votes secured by loser

= 85% - 15%

=70% =6300

Votes by the losing candidate = x = 15%

x = (15 * 6300)/70

x =(94500/70)

x = 1350

Discussion