Problems On Trains Aptitude Questions and Answers
This section focuses on "Problems on Trains" of Quantitative Aptitude. These Multiple Choice Questions (mcq) should be practiced to improve the Quantitative Aptitude skills required for various interviews (campus interviews, walk-in interviews, company interviews), placements, entrance exams and other competitive examinations.
1. A train running at the speed of 72 km/hr crosses a man standing on the platform in 12 seconds. What is the length of the train?
Explanation: Speed = (72*5)/18=20m/s
Length of the train = (Speed x Time).
Length of the train = 20*12=240m
2. A train 100 metres long and travelling at 54 km/hr can cross the bridge in 20 seconds, What will be length of the bridge?
Explanation: Speed = (54*5)/18=> 15m/sec
Time = 20 sec.
Let the length of bridge be x metres.
Then, (100 + x)/20 = 15
100 + x = 300
x = 200 m.
3. A train 210 m long passes a man standing in 21 seconds. How long will it take to pass a bridge of 500 m long?
Explanation: Speed = 210/21 => 10m/s
Required time = (210+500)/10 => 71 sec
4. Two trains 100 m and 150 m long run at the speed of 36 km/hr and 54 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:
Explanation: Relative speed = (36 + 54) km/hr = 90 km => 25 m/s
Distance covered in crossing each other = (100 + 150) m = 250 m.
Required time = 250 x 25 sec = 10 sec.
5. How many seconds will a 500 metre long train take to cross a man walking with a speed of 6 km/hr in the direction of the moving train if the speed of the train is 66 km/hr?
Explanation: Speed of the train relative to man = (63 - 3) km/hr = 60 km/hr => 50/3 m/s
Time taken to pass the man = (500*3)/50 => 30sec.
6. Two, trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is:
Explanation: Let us name the trains as A and B. Then,
(A's speed) : (B's speed) = root(b) : root(a) = root(16) : root(9) = 4 : 3.
7. A train 135m long is moving at a speed of 12.5 km/h. It will cross a girl coming from the opposite direction
at a speed of 1km/hr in.
Explanation: Relative speed = speed of train + speed of girl => (12.5 + 1) km/hr => 13.5 km/hr => 3.75 m/s
Time = distance / speed
Time taken by the train to pass the man = 135 / 3.75
= 36 sec.
8. The Mumbai express 500m long passes a man running at 20km/hr in the same direction in which the
express is going in 40sec. The speed of the express is.
Explanation: Length of the train = 500m
Speed of the expess relative to man = (500 / 40)m/s => 25/2 m/s => 45km/hr
Let the speed of the express be 'x' km/hr
Then the relative speed = (x -20)km/hr
Therefore x – 20 = 45 => x = 45 + 20 => 65km/hr
9. Two trains A and B are moving in opposite directions at 180 km/hr and 270 km/hr. their lengths are 3.30
km and 2.7 km respectively. The time taken by the slower train to cross the faster train in second is.
Explanation: Relative speed = (180 + 270)km/hr => 450 km/hr => 125m/s
Distance covered = (3.30 + 2.70)km => 6000m
Required time = 6000 / 125 => 48sec
10. A train M speeding with 60km/hr crooses another train N, running in the same direction in 1 min. If the
lengths of the trains M and N be 50m and 100m respectively. What is the speed of train N?
Explanation: Let the speed of be train N be 'x' km/hr
Speed of M relative to N = (60 – x)km/hr
=> (60-x) * (5/18)m/s
=> (300 – 5x / 18)m/s 150 / (300 – 5x / 18) =60 =>
x= 153/3 => x=51km/hr.