TCS Quantitative Aptitude Questions And Answers - TCS
TCS Quantitative Aptitude MCQs : This section focuses on "Quantitative Aptitude" of TCS Exam. These Quantitative Aptitude MCQs are asked in previous TCS NQT Exams and will help you to prepare for upcoming TCS NQT exam.
1. In a 400 meters race, X beats Y by 40 meters, while in a 200 meters race, Y beats Z by 10 meters. X beats Y in a kilometer race by?
A. 100 meters
B. 125 meters
C. 140 meters
D. 145 meters
View Answer
Ans : D
Explanation: When A = 400, B = 360.
When B = 200, C = 190.
Multiple A and B and C by 2.5
A = 400 * 2.5 = 1000
B = 360 * 2.5 = 900
C = will be 855
Make B = 900. A will be 1000. C will be 855.
2. The index numbers of five commodities are 100, 105, 110, 115, 120 and the weights assigned to these are respectively 5, 10, 5, 8, 15. Then what is the weighted average index number?
A. 100.57
B. 105.69
C. 112.09
D. 117.17
View Answer
Ans : C
Explanation: Weighted average = Sum of all the weights / Total number of weights
Sum of all the weights = 100*5 + 105*10 + 110*5 + 115*8 + 120*15
= 4820
Number of weights = 5 + 10 + 5 + 8 + 15
= 43
Weighted average = 4820 / 43
= 112.09
3. Ten years ago, the combined ages of X and Y was twice that of Z. If the sum of the ages of X and Y, fifteen years hence, is 98 years, what is the present age of Z?
A. 28 Yrs
B. 34 Yrs
C. 38 Yrs
D. 44 Yrs
View Answer
Ans : B
Explanation: (X -10)+(Y-10) =2(Z-10)
X + Y – 20 = 2Z – 20
X + Y = 2Z
X+Y+30= 98
X+Y=68
Z = 68 / 2
=34 yrs.
4. The average weight of 20 a group of mens increases by 5 kg when a new person replaces one of the men from the group who weighs 80kg. Calculate the weight of the new men.
A. 140 kg
B. 160 kg
C. 180 kg
D. 200 kg
View Answer
Ans : C
Explanation: Total increase in weight = 20*5 =100 kg
Weight of new person = 80+100 =180 kg
5. When 50% of a number is added to 100, the result is the same number. The number is?
A. 50
B. 100
C. 150
D. 200
View Answer
Ans : D
Explanation: Let the number be equal to x.
x/2 +100 = x
Hence x=200
6. In a class there are 40% of girls of which 20% poor. What is the probability that a poor girl is selected is leader?
A. 0.08
B. 0.12
C. 0.15
D. 0.2
View Answer
Ans : A
Explanation: Assume total students in the class = 100
Then Girls = 40% (100) = 40
Poor girls = 20% (40) = 8
So probability that a poor girls is selected leader = (Poor Girls/Total Girls)
= 8/100 => 8%
7. X and Y each walk 10 km. The speed of X is 1.5 faster than Y speed . X reaches the destination 1.5hrs before Y .Then X speed is equal to?
A. 2
B. 3
C. 4
D. 5
View Answer
Ans : C
Explanation: Let speed of X = x kmph.
So, speed of Y = ( x - 1.5 ) kmph.
Time difference =1.5hours
Total Distance = 10km
10/(x-1.5) -10/x = 1.5
By solving the above eq.
x = 4 kmph
8. Of a set of 30 numbers, average of first 10 numbers = average of last 20 numbers. Then the sum of the last 20 numbers is?
A. Sum of first ten numbers
B. 2X sum of first 10 number
C. Sum of last ten number
D. 2X sum of last ten number
View Answer
Ans : B
Explanation: since, average=(sum of n no.s)/(total no)
therefore, (sum of first 10 no.s)/10 == (sum of last 20 no)/20
Hence, (sum of last 20 no.s) = 2*(sum of first 10 no.s)
9. In a particular year, the month of march had exactly 4 friday and 4 monday On which day of the week did march 1st occur in the year?
A. tuesday
B. wednesday
C. thursdays
D. friday
View Answer
Ans : A
Explanation: If a month has 31 days, and it starts with Monday, Then Mondays,
tuesday, wednesday are 5 for that month. If this month starts
with tuesday, then tuesday, wednesday and thursdays
are 5 and remaining days are 4 each. so this month start with tuesday.
10. X takes 10 days to paint a house completely whereas Y require 15 days to paint the same house completely. How many days will take to paint the house if both them work together?
A. 3
B. 4
C. 5
D. 6
View Answer
Ans : D
Explanation: work done by x in day=1/10
work done by other in a day=1/15
work done by both in a day=1/10 +1/15 = 5/30
days required by both = 30/5 = 6 days
11. At present, the ratio between the ages of Amit and Dhiraj is 5 : 4. After 6 years, Amit’s age will be 26 years. What is the age of Dhiraj at present?
A. 12 years
B. 17 years
C. 16 years
D. 21 years
View Answer
Ans : C
Explanation: Let the present ages of Amit and Dhiraj be 5x years and 4x years respectively. Then,
5x + 6 = 26
5x = 20
x = 4
Dhiraj’s age = 4x = 16 years
12. The average of 9 observations was 9, that of the 1st of 5 being 10 and that of the last 5 being 8. What was the 5th observation?
A. 6
B. 7
C. 8
D. 9
View Answer
Ans : D
Explanation: 1 to 9 = 9 * 9 = 81
1 to 5 = 5 * 10 = 50
5 to 9 = 5 * 8 = 40
5th = 50 + 40 = 90 – 81 = 9
13. How many prime numbers less that 100 and greater than 3 are of the form:4x+1 , 5y-1?
A. 29, 89
B. 39, 12
C. 37, 14
D. 34, 19
View Answer
Ans : A
Explanation: The primes p such that 3 < p < 100 and of the form 4x+1 are 5, 13, 17, 29, 37, 41, 53, 61, 73, 89 and 97. These are eleven in number.
The primes of the form 5y-1 are 19, 29, 59, 79, and 89 and these are five in number. Only two of these viz. 29 and 89 are in both the lists.
Both the lists taken together do not exhaust all the primes in this range, and 7, 11, 23, 31, 43, 47, 67, 71, and 83 do not appear in either of the lists.
Hence, there are only two numbers i.e., 29, and 89
14. A bag contains 8 white balls and 3 blue balls. Another bag contains 7 white and 4 blue balls. What is the probability of getting blue ball?
A. (7/22)
B. (3/7)
C. (7/25)
D. (7/15)
View Answer
Ans : A
Explanation: First we have to select a bag and then we will draw a ball.
Probability of selection of both bags is equal =1/2
Now probability of blue ball taken from first bag = ( 1/2) x (3/11)
and probability of blue ball taken from second bag = (1/2) x (4/11)
So probability of blue ball = ( 1/2) x (3/11) + (1/2) x (4/11) = 7/22
15. In paper A, one student got 18 out of 70 and in paper B he got 14 out of 30. In which paper he did fare well?
A. Paper A
B. Paper B
C. Equally
D. None of the above
View Answer
Ans : B
Explanation: Paper A:(18/70)*100~=25.71%
Paper B:(14/30)*100~=46.66%
Therefore the solution is Paper B
16. A man buys a cycle for Rs. 1400 and sells it at a loss of 15%. What is the selling price of the cycle?
A. Rs 1090
B. Rs 1160
C. Rs 1190
D. Rs 1202
View Answer
Ans : C
Explanation: S.P. = 85% of Rs. 1400
= Rs. (85/100) * 1400
= Rs. 1190
17. A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
A. 15 days
B. 20 days
C. 12 days
D. 9 days
View Answer
Ans : A
Explanation: one day work done by A=1/20
work done by A in 2 days=1/10
work done by A,B,C on 3rd day=1/20+1/30+1/60=1/10
total work done in 3 days= 1/10+1/10= 1/5
1/5th of the work will be completed at the end of 3 days
the remaining work =1-1/5=4/5
4/5 of work will be completed 1/5*5/4*3= 12 days
total work wiil be done in 3+12 =15 days
18. What is the angle between two hands when time is 5:30?
A. 45°
B. 30°
C. 15°
D. 60°
View Answer
Ans : C
Explanation: Hour hand makes 360° in its complete rotation, i.e 12 hrs makes 360° or we can say 12hrs*60minutes=720 minutes makes 360°. So hour hand makes 360°/720minutes=0.5°/minute.
Minutes hand makes 360° in its complete rotation, i.e is 60 minutes makes 360°. So minute hand makes 360°/60minutes= 6°/minutes.
Now According to question,
Hour hand will make total angle from mark 12 in clockwise direction ,
0.5°*(60*5+30)=165°
Minute hand will make angle from mark 12 in clockwise direction,
6°*30=180°
So angle between two hands=180-165=15°
19. A and B income in the ratio of 5:4,and where expenditure in the ratio of 14:11 if they saves 1000 rs each then what is the total income of A?
A. 17000
B. 15000
C. 15500
D. 14500
View Answer
Ans : B
Explanation: 5x-1000/4x-1000=14/11 => x=3000. hence, Income of A = 5x = 5*3000 = 15000.
20. A series 1234123441234441234444.....n what is the value on 200th position..??
A. 1
B. 2
C. 3
D. 4
View Answer
Ans : D
Explanation: 1234 => 4 times
12344 => 5 times
123444 => 6 times
4 + 5 + 6 + ...n < 200 n(n+1)/2 - 6 = 200 So n = 19 i.e. 4+5+6+...19 = 184 After the 184th term,the sequence has 20 terms 12344444444444444444 = 20 terms => 200th term = 4
Discussion