Wipro Quantitative Aptitude Questions And Answers
Wipro Quantitative Aptitude MCQs : This section focuses on "Quantitative Aptitude" for Wipro recruitment exam. These Quantitative Aptitude MCQs are asked in previous Wipro placements/recruitment exams and will help you to prepare for upcoming Wipro drives.
1. The least perfect square, which is divisible by each of 5, 15 and 35 is?
A. 10125
B. 7056
C. 7350
D. 11025
View Answer
Ans : D
Explanation: L.C.M. of 5, 15, 35 = 105
Now, 1820= 5 * 3 * 7
To make it a perfect square, it must be multiplied by 5 * 3 * 7
So, required number = 5 * 3 * 7
= 25 * 9 * 49 = 11025
2. A and B are two number when divided by 4 leaves a remainder 2 and 1. What will be the remainder when A+B is divided by 4 ?
A. 4
B. 7
C. 11
D. 13
View Answer
Ans : B
Explanation: A=4a+2
B=4b+1
A+B=4(a+b)+3
A+B=4(a-b)-4+4+3 [by adding -4 and +4]
A+B=4(a+b-1)+7
As seen above, if we divide A+B by 4, the remainder will be 7.
3. Both X and Y randomly choose a colour from black, blue, and white. What is the probability that both choose orange?
A. (1/3)
B. (2/9)
C. (1/9)
D. (2/3)
View Answer
Ans : C
Explanation: There are three different colours possible to be chosen.
Probability that X chooses orange colour = 1/3
(blue is 1 among the 3 possible colours)
Probability that Y chooses blue colour = 1/3
Probability that both X and Y choose blue colour = 1/3 × 1/3 = 1/9
4. By what number should be 17325 divided to make it a perfect square?
A. 7x11
B. 5x13
C. 5x7
D. 11x13
View Answer
Ans : A
Explanation: First Prime Factorize 17325, that Gives;
17325 = 3*3*5*5*7*11
As a factor of 7*11 is not in Pair.
17325 should be divided by 7*11 to get a Perfect Square
i.e. 17325/(7*11) = 225
5. The sum of a number and the two numbers preceding it is equal to 30. Find the number:
A. 7
B. 8
C. 9
D. 10
View Answer
Ans : C
Explanation: X+Y+Z=30 ---- 1
Y=X-1 ------ 2
Z=X-2 ------ 3
Put 2 and 3 in 1
X+X-1+X-2 = 30
3X = 27
X = 9
6. Sanjay invested an amount of Rs 16,000 for two years on compound interest and received an amount of RS 17,640 on maturity. What is the rate of interest per annum?
A. 0.05
B. 0.06
C. 0.07
D. 0.08
View Answer
Ans : A
Explanation: Amount =P(1+r/100)^2
17640/16000= (1+r/100)^2
441/400= (1+r/100)^2
=> (21/20)^2= (1+r/100)^2
R=5%
7. X can do 20% of a piece of work in 5 days. How many days will he take to complete the work five times ?
A. 100 days
B. 125 days
C. 150 days
D. 200 days
View Answer
Ans : B
Explanation: x is completing 20% of the work in 5 days he will complete 100% of the work in
(100/20) x 5 = 25 days
If x will complete 100% of the work in 25 days then he will complete 5 times the work in 25 x 5 = 125 days.
8. A tap having a diameter(d) can empty a tank in 84 min. How long another tap having diameter 2d take to empty the same tank?
A. 21 mins
B. 25 mins
C. 27 mins
D. 36 mins
View Answer
Ans : A
Explanation: Area = work done
Area = πr*r
Since it is square of radius when radius or diameter doubles its area becomes 4 times
When area becomes 4 times work done also becomes 4 times
So time taken by tap with diameter 2d to empty the tank = 84/4 =21 mins
9. In a stream running at 2 km/h, a motor boat goes 10 km upstream and back again to the starting point in 55 min. The speed of the motorboat in still water is
A. 19 km/h
B. 20 km/h
C. 21 km/h
D. 22 km/h
View Answer
Ans : D
Explanation: Let "x" be the speed of Motor boat in still water
Distance = 10 km; Time = 55/60 hrs
For upstream, the speed of motorboat = x - 2
For downstream, the speed of motorboat = x + 2
55 / 60 = 10/ (x – 2) + 10/(x + 2) So, x = 22.
10. For Question, if subsequently in 1983, the cost of labor and overheads increased by 30%, and 10% respectively, calculate the cost of manufacturing in 1983.
A. 360
B. 740
C. 1080
D. 920
View Answer
Ans : B
Explanation: The costs in 1983 were 400 and 200 respectively. An increase of 30% in labor Æ increase of 120.
Increase of 10% in overheads increase of 20.
Total Increase = 120 + 20 = 140.
New cost = 600 + 140 = 740
11. A man can row 4.5 km/h in still water and he finds that it takes him twice as long to row up as to row down the river. The speed of the stream is
A. 2.5 km/h
B. 1.5 km/h
C. 2 km/h
D. 1.75 km/h
View Answer
Ans : B
Explanation: Let speed of stream be S and x be upstream speed.
Then for downstream, 4.5 + S = D
And for upstream , 4.5 – S = U
So we get, D + U = 9
But, it takes him twice as long to row up as to row down the river.
3U = 9 ; U = 3. Thus, 4.5 – S = 3
S=1.5 kmph
12. A boat takes 19 hours for travelling downstream from point A to point B and coming back to a point C midway between A and B. If the velocity of the stream is 4 km/h and the speed of the boat in still water is 14 km/h, what is the distance between A and B?
A. 200 km
B. 160 km
C. 180 km
D. 220 km
View Answer
Ans : C
Explanation: Speed of boat for downstream = 14 + 4 = 18 km/hr
Speed of boat for upstream = 14 – 4 = 10 km/hr
Distance = x
x / 18 + (x /2)/10 = 19
x = 180 km
13. Find the greatest number that will divide 355, 54 and 103 so as to leave the same remainder in each case.
A. 4
B. 7
C. 9
D. 13
View Answer
Ans : B
Explanation: Required number = H.C.F. of |a -b|, |b – c| and |c – a|
= H.C.F. of |355 – 54|, |54 – 103| and |103 – 355|
= 301, 49, 252
= 7
14. Six bells commence tolling together and toll at intervals of 3, 6, 9, 12, 15 and 18 seconds respectively. In 60 minutes, how many times do they toll together ?
A. 10
B. 20
C. 21
D. 15
View Answer
Ans : C
Explanation: L.C.M. of 3, 6, 9, 12, 15 and 18 is 180.
So, the bells will toll together after every 180 seconds(3 minutes).
In 60 minutes, they will toll together (60/3)+1 = 21 times.
15. A can do a work in 10 days and B in 15 days. If they work on it together for 3 days, then the work that is left is :
A. 0.1
B. 0.2
C. 0.4
D. 0.5
View Answer
Ans : D
Explanation: Let the total work to be done is, say, 30 units.
A does the work in 10 days,
So A’s 1-day work = (30 / 10) = 3 units
B does the work in 15 days,
So B’s 1-day work = (30 / 15) = 2 units
Therefore, A’s and B’s together 1-day work = (3 + 2) = 5 units
In 3 days, work done = 5 * 3 = 15 units
amount of work left = 30 – 15 = 15 units
Therefore the % of work left after 3 days = (15 / 30) * 100% = 50%
16. Pipe P can fill a cement tank in 24 hours. However, there is a leakage at the bottom of the tank due to which the Pipe P takes 12 hrs longer and fills it in 36 hours. How long would this leakage take to empty the entire tank?
A. 48 hours
B. 60 hours
C. 72 hours
D. 96 hours
View Answer
Ans : C
Explanation: Normally, Pipe P can fill the cement tank in 24 hours. So in 1 hour, it fills = 1/24 part of tank
Due to leak, Pipe P can fill the tank in 36 hours. So in 1 hour it actually fills = 1/36 part of tub
∴ Water removed by the leak in 1 hour = (1/24) - (1/36) = (1/72)
∴ Leak empties the tank in 72 hours.
17. The average age of husband, wife and their child 6 years ago was 33 years and that of wife and child 8 years ago was 32 years. The present age of the husband is
A. 32 years
B. 37 years
C. 42 years
D. 47 years
View Answer
Ans : B
Explanation: Average age of husband, wife and child = 33
Number of people = 3
Sum of present age = 33 imes 333×3
6 years ago
Sum of the present ages of husband, wife and child = (33 imes 3 + 6 imes 3)(33×3+6×3)years = 117 years.
Similarly,
Sum of the present ages of wife and child = 32*2 + 2*8 years = 80 years.
Husbands present age = (117 - 80) years = 37 years.
18. An untrustworthy vendor affirms to sell his products at Cost Price yet at the same time gets a 20% benefit by utilizing a bogus weight. What weight does he substitute for a kilogram?
A. 833 1/3 GRAMS
B. 833 2/3 GRAMS
C. 834 1/3 GRAMS
D. 835 2/3 GRAMS
View Answer
Ans : A
Explanation: If the cost price is Rs.100, then to get a profit of 20%, the selling price
should be Rs.120.
If 120kg is to be sold, and the dealer gives only 100kg, to get a profit of 20%.
How many grams he has to give instead of one kilogram(1000 gm).
120 gm ------ 100 gm
1000 gm ------ ?
(1000 * 100)/120 = 2500/3 = 833 1/3 grams.
19. A certain sum of money amounts to Rs 704 in 2 years and Rs 800 in 5 years . Find the rate percentage per annum for simple interest
A. 0.08
B. 0.13
C. 0.02
D. 0.05
View Answer
Ans : D
Explanation: Assuming Simple interest
P + (P*R*2)/100 = 704.......(i)
P + (P*R*5)/100 = 800.......(ii)
on solving (i) and (ii)
3PR/100 = 96
PR = 3200
P + (P*R*2)/100 = 704
P + (3200*2)/100 = 704
P = 704 - 64 = 640
PR = 3200
640 R = 3200
R = 5 %
rate of interest per annum = 5 %
20. It takes four and a half hours by a jetski to 30 km downstream and comes back in still water at the rate of 15Kmph. Determine the speed of the stream.
A. 4.5 km/hr
B. 6 km/hr
C. 7 km/hr
D. 4.48 km/hr
View Answer
Ans : D
Explanation: Let the speed of the stream be x km/hr. Then,
Speed downstream = (21 + x) km/hr,
Speed upstream = (21 - x) km/hr.
9x^2 =181
x = 4.48 km/hr.
Discussion