# Publicis Sapient Quantitative Aptitude Questions

Publicis Sapient Quantitative Aptitude MCQs : This section focuses on "Quantitative Aptitude" for Publicis Sapient Exam. These Quantitative Aptitude MCQs are asked in previous Publicis Sapient placements/recruitment exams and will help you to prepare for upcoming Publicis Sapient drives.

1. H.C.F. of 513, 1134 and 1215 is _

A. 18

B. 27

C. 33

D. 36

View Answer

Ans : B

Explanation: Finding H.C.F. by division method: H.C.F. of 513, 1134 and 1215 = 3 × 3 × 3 = 27.

2. 3/7 of the oranges grown are too sour to eat out 3,80,205 oranges that are grown on a farm. The owner has to sell the eatable Orange. How many Oranges can the farm owner sell?

A. 162945

B. 217260

C. 325890

D. 434520

View Answer

Ans : B

Explanation: Given that : 3/7 of oranges are sour to eat. Total no. of oranges = 3,80,205 Sour oranges = 3/7 of 3,80,205 = 3 × 54315 = 162945 Oranges that can be sold = total no. of oranges - sour oranges = 3,80,205 - 1,62,945 = 2,17,260 so 2,17,260 oranges can be sold by the farmer.

3. If Shalu buys 6 more apples, his carton will weigh 14.5 kilograms. If the weight of one apple is 250 grams. How many apples did he initially had in his carton?

A. 58

B. 52

C. 56

D. 54

View Answer

Ans : B

Explanation: Weight of 1 apple = 250 g

Weight of 6 apples = 250 * 6 =>= 1.5 kg

Initial weight = 14.5 - 1.5 => 13 kg

Number of apples in his carton initially := 13000/250 => 52 apples

4. The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:

A. 127

B. 305

C. 235

D. 123

View Answer

Ans : A

Explanation: Required number = H.C.F. of (1657 - 6) and (2037 - 5) => H.C.F. of 1651 and 2032 = 127.

5. When the integer n is divided by 8, the remainder is 3. What is the remainder if 6n is divided by 8?

A. 4

B. 1

C. 2

D. 3

View Answer

Ans : C

Explanation: When n is divided by 8, the remainder is 3 may be written as

n = 8 k + 3

multiply all terms by 6

6 n = 6(8 k + 3) = 8(6k) + 18

Write 18 as 16 + 2 since 16 = 8 * 2.

= 8(6k) + 16 + 2

Factor 8 out.

= 8(6k + 2) + 2

The above indicates that if 6n is divided by 8, the remainder is 2.

6. By what number should be 86700 divided to make it a perfect square?

A. 2

B. 5

C. 4

D. 3

View Answer

Ans : D

Explanation: First Prime Factorize 86700, that Gives;

86700 = 2×2×5×5×3×17×17

As factor of 3 is not in Pair.

86700 should be divided by 3 to get a Perfect Square

i.e.- 86700/3 = 28900

7. A merchant sold an article at 10% loss. If he had sold it Rs 450 more, 8% would have been gained on the cost price. Find the cost price?

A. Rs 1200

B. Rs 1800

C. Rs 2500

D. Rs 1500

View Answer

Ans : C

Explanation: Let the cost price be 100%. It is sold at 10% loss. So it is sold at

90% of the cost price.

90 % of the cost price

+ 450 = 108% of the Cost price

18% of the cost price = Rs 450

Cost price of the book = 450/18 x 100 = Rs 2500

8. Rs.8000 become Rs.9261 in a certain interval of time at the rate of 5% per annum of C.I. Find the time?

A. 4 years

B. 3 years

C. 6 years

D. 2 years

View Answer

Ans : B

Explanation: P = 8000

CI = 9261

R = 5% PER ANNUM

9261 = 8000( 1+5/100)^n

8000(1+5/100)^n

(21/20)^n= 9261/8000

(21/20) ^n =( 21/20)^3

n= 3

9. Two trains of equal length, running in opposite directions, pass a pole in 18 and 12 seconds. The trains will cross each other in

A. 15.5 sec

B. 14.4 sec

C. 18.8 sec

D. 20.2 sec

View Answer

Ans : B

Explanation: Let the length of the train be L metres

Speed of first train = 360018xL360018xL m/hour

Speed of secxond train = 360012xL360012xL m/hour

When running in opposite directions, relative speed = 200 L + 300 L m/hour

Distance to be covered = L + L = 2L metre

Time taken = 2L500Lx36002L500Lx3600 sec

=14.4 sec

10. In a dairy farm, 40 cows eat 40 bags of husk in 40 days. In how many days one cow will eat one bag of husk?

A. 10

B. 25

C. 40

D. 80

View Answer

Ans : C

Explanation: 1 x 40 x x = 40 x 1 x 40

Discussion