Goldman Sachs Quantitative Aptitude Questions And Answers
Goldman Sachs Quantitative Aptitude MCQs : This section focuses on "Quantitative Aptitude" for Goldman Sachs Exam. These Quantitative Aptitude MCQs are asked in previous Goldman Sachs placements/recruitment exams and will help you to prepare for upcoming Goldman Sachs drives.
1. If 5 students utilize 18 pencils in 9 days, how long at the same rate will 66 pencils last for 15 students?
Explanation: Required number of days = 9 X 5/15 X 66/18 = 11 days
2. The tax on a commodity is diminished by 10 % and its consumption increased by 10 %. The effect on the revenue derived from it changes by K %. Find the value of K.
Explanation: Directly using the formula, when a value is increased by R% and then decreased by R%, then net there is R2/100% decrease.
Putting R = 10, we get 1 % decrease.
3. A portion of a 30 m long tree is broken by a tornado and the top strikes the ground making an angle of 30° with the ground level. The height of the point where the tree is broken is equal to
Explanation: The height of the tree = 30m.
So, x + y = 30m
Also sin30∘ 1/2 = x/y x = 2y.
So 3x = 30,
x = 10 m.
4. Fill pipe A is 3 times faster than second Fill pipe B and takes 32 minutes less than Fill pipe B. When will the cistern be full if both pipes are opened together?
Explanation: Let the time taken by A to fill the pipe is = A min.
So the time taken by B to fill the pipe B is = B min.
According to the given condition B = 3A;
and given that B – A = 32 min.
So solving we get A = 16 min, B = 48 min.
Let the total work be 48 units.
So time taken by them together is 48/4 = 12 min.
5. A year is selected at random. What is the probability that it contains 53 Mondays if every fourth year is a leap year?
Explanation: Let P(L) = probability of selecting a leap year. P(NL) = probability of selecting a non - leap year. P(M) = probability of getting 53 Mondays in a year.
P(M)=P(M|L)P(L)+P(M|NL)P(NL) (By law of probability)
= 2/7 * 1/4 + 1/7 * 3/4 => 5/28
6. A man walks 6 km at a speed of 1 1/2 kmph, runs 8 km at a speed of 2 kmph and goes by bus another 32 km. Speed of the bus is 8 kmph. Find the average speed of the man.
Explanation: Man walked 6 km at 1.5 kmph, again he walked 8 km at speed of 2 kmph and 32 km at a speed of 8kmph time taken individually:
=> 6/1.5 = 4 m
=> 8/2 = 4 m
=> 32/8 = 4 m
Average speed of man= total distance/ total time
=> 46/12 = 3 (5/6)
7. A boat can travel at a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.
Explanation: Speed downstream = (13 + 4) km/hr = 17 km/hr
Time is taken to travel 68 km downstream = (68/17)=4 hours
8. What least number must be added to 1056, so that the sum is completely divisible by 23 ?
Explanation: Required number = (23 - 21)
9. A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
Explanation: Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 110 - (60) => 50.
Required percentage= ((50/110) * 100) = 45(5/11)%
10. Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case .
Explanation: Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.