Infosys Quantitative Aptitude Questions And Answers
Infosys Quantitative Aptitude MCQs : This section focuses on "Quantitative Aptitude" of Infosys Exam. These Quantitative Aptitude MCQs are asked in previous Infosys Recruitment Exams & drives for freshers and will help you to prepare for upcoming exams and recruitment drives.
1. A cricket player scored 150 runs which included 5 boundaries and 10 sixes. What percent of his total score did he make by running between the wickets?
A. 0.1
B. 0.15
C. 0.2
D. 0.25
View Answer
Ans : C
Explanation: Number of runs made by running = 150 - (5 x 4 + 10 x 6)
= 150 - (80)
= 30.
Required percentage = (30/150)*100 = 20%
2. 6 members need to be selected from different field. In such a way that 10 from java, 5 from Microsoft,8 from Oracle,2 from IBM. What is the possible combination?
A. 5
B. 120
C. 12880
D. 168000
View Answer
Ans : D
Explanation: 10C1*5C1*8C1*2C1*21C2=168000
IN EVERY FIELD ONE MEMBER IS SELECTED AND IN REMAINING 21 WE SELECT 2 MEMBER.
3. There were two candidates in an election. Winner candidate received 60% of votes and won the election by 240 votes. Find the number of votes cast to the winning candidate?
A. 360
B. 720
C. 1080
D. 800
View Answer
Ans : B
Explanation: W = 60% L = 40%
60% - 40% = 20%
20% OF 240 = 12
60% -------- ? => 720
4. A tank is 20 m long, 15 m wide and 10 m deep. The cost of plastering its walls and bottom at 50 paise per sq. m, is:
A. Rs. 500
B. Rs. 600
C. Rs. 750
D. Rs. 650
View Answer
Ans : A
Explanation: Area to be plastered = [2(l+b)×h]+(l×b)
=[2(20+15)×10]+(20×15)
=1000sq.m
Cost of plastering = (1000×50)/100
= Rs.500
5. If X rows 20 km upstream in 4 hours and 30 km downstream in 3 hours, then the speed of the stream is
A. 1 kmph
B. 1.5 kmph
C. 2.0 kmph
D. 2.5 kmph
View Answer
Ans : D
Explanation: Rate upstream = (20/4) kmph = 5 kmph
Rate downstream (30/3) kmph = 10 kmph.
Speed of stream (1/2)(10 - 5)kmph = 2.5 kmph
6. If X spends every day 45 minutes for watering the plants how much time does X spend watering the plants in 20 days?
A. 10 hours
B. 12 hours
C. 15 hours
D. 20 hours
View Answer
Ans : C
Explanation: X 1 day sepend time = 45 min
X 20 days spend time =20*45min
=900 min
so, convert it into hours= 900/60 hrs = 15hrs
7. Ramesh bought a book for Rs 100 , Ramesh sold off to a friend for Rs 80 but after a while Ramesh felt sorry , that Ramesh sold it and bought it back for Rs 90, how much loss did Ramesh incur?
A. Rs. 5
B. Rs. 10
C. Rs. 15
D. Rs. 20
View Answer
Ans : B
Explanation: cp of book=100
sp of book=80
profit=20
again cp=90
then loss =90-80=10
8. A is 60 years old and B is 80 years old. How many years ago was the ratio of their ages 4 : 6?
A. 10 Years
B. 15 Years
C. 20 Years
D. 25 Years
View Answer
Ans : C
Explanation: Let us assume x years ago
At present: A is 60 years and B is 80 years
x years ago: A age = (60 – x) and Y age = (80 – x)
Ratio of their ages x years ago was 4 : 6
(60 – x)=4
(80 – x)=6
6(60 – x) = 4(80 – x)
360 – 6x = 320 – 4x
x = 20
Therefore, 20 years ago, the ratio of their ages was 4 : 6
9. Which digit should come in the place of * and # if the number 62684*# is divisible by both 8 and 5 ?
A. 4 and 0
B. 0 and 5
C. 5 and 0
D. 2 and 0
View Answer
Ans : A
Explanation: Since the given number is divible by 5,So 0 or 5 must come in place of * .But a number ending with 5 is never divisible by 8.Therefore 0 will be in units place
The number formed by the last 4 digit is 4 *0which becomes divisible by 8, if * is replaced by 4.
10. 1254 + 165.302 – ? = 1200.00
A. 211.302
B. 217.698
C. 219.302
D. 223.698
View Answer
Ans : C
Explanation: Let 1254 + 165.302 - x = 1200.00
Then x = (1254 + 165.302) - 1200.00
= 1419.302 - 1200.00
= 219.302
11. If 20% of a = b, then b% of 20 is the same as:
A. 4% of a
B. 5% of a
C. 20% of a
D. None of these
View Answer
Ans : A
Explanation: 20% of a = b
=> (20/100)a = b
therefore, b% of 20 = (b/100)*20
= (20a/100)*(1/100)*20
= 4a/100 = 4% of a.
12. 99! how many zero's?
A. 19
B. 31
C. 14
D. 22
View Answer
Ans : D
Explanation: No. of zeros means to check what is the total no. of factors of 2 and 5 when no. is divided by both. consider lowest no. of factors
i.e. 99/2=49, 49/2=24, 24/2=12, 12/2=6, 6/2=3, 3/2=1.
Therefore total no. of factors of 2=49+24+12+6+3+1=95
now 99/5=19, 19/5=3.
therefore total no. of factors =19+3=22
now take the lowest one....so 22 no. of zero in 99!
13. Two dice are thrown simultaneously. What is the probability that the sum of the numbers shown on the two dices will be a prime number?
A. 17/36
B. (1/2)
C. 15/36
D. (7/18)
View Answer
Ans : C
Explanation: number of sample solution=36
number of possible outcomes=(1,1),(1,2),(1,4),(1,6),(2,1),(2,3),(2,5),
(3,2)(3,4)(4,1)(4,3)(5,2)(5,6)(6,1)(6,5)=15
p=15/36
14. No. of triangles formed in a polygon having 15 sides is?
A. 400
B. 355
C. 353
D. 455
View Answer
Ans : D
Explanation: total no. of points=15
no. of points needed to form a triangle=3
thus total no of triangles formed= 15C3 = 455.
15. One gear pulley rotates at a speed of 3 rev/sec another gear roates at 5 rev/sec. if both start together after how many seconds will they be together again?
A. 3 sec
B. 20 sec
C. 15 sec
D. 5 sec
View Answer
Ans : C
Explanation: 3 rotates 3,6,9,12,15
5 rotates 5,10,15
because ans is 15
16. In a grass field if 40 cows could eat for 40 days.The same grass field can feed 30 cows for 60 days.how long will it feed 20 cows?
A. 80
B. 85
C. 70
D. 60
View Answer
Ans : A
Explanation: you can solve by ratio
40C : 40D --> 1:1
30C : 60D --> 1:2
20C : 80D --> 1:4
ans:80
17. If the list price of a book is reduced by Rs. 5, then a person can buy 5 more books for Rs. 300. The original cost of the book is
A. Rs. 15
B. Rs. 20
C. Rs. 25
D. Rs. 30
View Answer
Ans : B
Explanation: If x is earlier price, then
300/(x-5)- 300/x = 5
solving this , we get, x=20 or -15 out of which only 20 is acceptable.
18. Rahul is 15 years elder than Rohan. If 5 years ago, Rahul was 3 times as old as Rohan, then find Rahul's present age.
A. 32.5 years
B. 27.5 years
C. 25 years
D. 24.9 years
View Answer
Ans : B
Explanation: 1) Let age of Rohan be y
2) Rahul is 15 years elder than Rohan = (y + 15). So Rahul’s age 5 years ago = (y + 15 – 5)
3) Rohan’s age before 5 years = (y – 5)
5 years ago, Rahul is 3 times as old as Rohan
(y + 15 – 5) = 3 (y – 5)
(y + 10) = (3y – 15)
2y = 25
y = 12.5
Rohan’s age = 12.5 years
Rahul’s age = (y + 15) = (12.5 + 15) = 27.5 years
19. If an integer n is divisible by 3, 5 and 12, what is the next larger integer divisible by all these numbers?
A. n + 3
B. n + 5
C. n + 12
D. n + 60
View Answer
Ans : D
Explanation: n is divisible by 3, 5 and 12 it must a multiple of the lcm of 3, 5 and 12 which is 60.
n = 60 k
n + 60 is also divisible by 60 since
n + 60 = 60 k + 60 = 60(k + 1)
20. 8. 3889 + 12.952 –? = 3854.002
A. 47.015
B. 47.641
C. 47.943
D. 47.95
View Answer
Ans : D
Explanation: Let 3889 + 12.952 - x = 3854.002.
Then x = (3889 + 12.952) - 3854.002
= 3901.952 - 3854.002
= 47.95
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