# Quantitative Aptitude Questions and Answers - Problems on Ages

11. Amit is 18 years elder than Rohit. If 8 years ago, Amit was 6 times as old as Rohit, then find Amit’s present
age.

A. 28.4 yrs

B. 29.6 yrs

C. 29.9 yrs

D. 31.3yrs

View Answer

Ans : B

Explanation: Let age of Rohit be y

Amit is 18 years elder than Rohit = (y + 18).

SoAmit’s age 8 years ago = (y + 18 – 8)

Rohit’s age before 8 years = (y – 8)

8 years ago, Amit is 6 times as old as Rohit

(y + 18 – 8) = 6 (y – 8)

(y + 10) = (6y – 48)

5y = 58

y = 11.6

Rohit’s age = 11.6years

Amit’s age = (y + 18) = (11.6 + 18) = 29.6years

12. 12 years ago M was half of N in age. If the ratio of their present ages is 4 : 5, what will be the total of their
present ages

A. 36 yrs

B. 35 yrs

C. 39 yrs

D. 33 yrs

View Answer

Ans : A

Explanation: Let M's age 12 years ago = x years.

Then, N's age 12 years ago = 2x years.

(x + 12) / (2x+ l2) = 4/5

=> x = 4.

So, the total of their present ages =(x + 12 + 2x + 12)

= (3x + 24) = 36 years.

13. The total age of x and y is 48 years more than the total age of y and z. z is how many year younger than x

A. 45 yrs

B. 46 yrs

C. 47 yrs

D. 48 yrs

View Answer

Ans : D

Explanation: Given that x+y = 48 + y+ z

x – z= 48 + y – y = 48

z is younger than x by 48 years

14. Eight years ago, the ratio of the ages of micky and Donald was 6:5, 12years hence, the ratio of their ages will be 11:10. What is Donald age at present

A. 16

B. 24

C. 28

D. 44

View Answer

Ans : C

Explanation: Let 8 years ago the age of Micky and Donald be 6x and 5x resp.

then,

((6x+8)+12) / ((5x+8)+12) = 11/10

10(6x+20) = 11(5x+20)

5x = 20 => x = 4

So Donald age is (5x+8) = 28

15. Keerthi's grandfather was 16 times older to her 32 years ago. He would be 6times of her age 16 years
from now. What was ratio of ages of keerthi and her grandfather 16 years ago.

A. 1:10

B. 11:10

C. 10:11

D. 10:11

View Answer

Ans : A

Explanation: Let, keerthi's age 32 years ago = x,

Grandfather's age 32 years ago = 16x.

16 years from now, 6(x+32+16) = (16x+32+16)

=> x = 24

16 years ago ratio was:

(x+16)/ (16x+16) = (24+16) / (16*24+16)

40 /400 = >1 :10

16. Total of the ages of P, Q and R at present is 99 years. Eight years ago, the ratio of their ages was 4: 5: 6.
What is the age of Q at present

A. 44

B. 30

C. 45

D. 33

View Answer

Ans : D

Explanation: Let their ages 8 years ago is4x, 5x and 6x years.

4x+8+5x + 8 + 6x + 8= 99

hence x= 5

Q’s present age = (5x + 8)

=33 years

17. The sum of ages of 4 puppies born at the intervals of 2 years each is 48 years. What is the age of the
youngest puppy?

A. 8yrs

B. 9yrs

C. 10yrs

D. 12yrs

View Answer

Ans : B

Explanation: Let the ages of puppies be x, (x + 2), (x + 4)and (x + 6) years.

Then, x + (x + 2) + (x + 4) + (x + 6) = 48

4x = 36,x = 9

Age of the youngest puppy = x = 9 years

18. P is 6 years older than Q who is twice as old as R. If the total of the ages of P, Q and R be 81, the how
old is Q?

A. 27

B. 28

C. 29

D. 30

View Answer

Ans : D

Explanation: Let R's age be x years.

Then, Q's age = 2x years.

P's age = (2x + 6) years.

(2x + 6) + 2x + x = 81

5x = 75=> x =15.

Hence, Q's age = 2x = 30 years

19. A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?

A. 8

B. 9

C. 10

D. 11

View Answer

Ans : C

Explanation: Let C's age be x years.

Then, B's age = 2x years.

A's age = (2x + 2) years.

(2x + 2) + 2x + x = 27

5x = 25

x = 5.

Hence, B's age = 2x = 10 years.

20. The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:

A. 12 yrs

B. 14 yrs

C. 18 yrs

D. 20 yrs

View Answer

Ans : D

Explanation: Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 6 = 5(x - 6)

54 - x = 5x - 30

6x = 84

x = 14.

Son's age after 6 years = (x+ 6) = 20 years.

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