Q. C# Program to Count the Number of Digits in a Number.
Here you will find an algorithm and program in C# programming language to count number of digits in a number. First let us understand this.
Explanation : Suppose an input number is given as 12341 then the output will be 5 as there are 5 digits in the given number and digits are 1, 2, 3, 4, 1.
Algorithm to count the number of digits in a given number
START step 1 : Input a number from user. Store it in some variable say num. step 2 : Initialize another variable to store total digits say digit = 0. step 3 : If num > 0 then increment count by 1 i.e. count++. step 4 : Divide num by 10 to remove last digit of the given number i.e. num = num / 10. step 5 : Repeat step 3 to 4 till num > 0 or num != 0. STOP
C# Program to Count Number of Digits in a Number
using System; class LFC { static int count_digit(long num) { int count = 0; while (num != 0) { num = num / 10; ++count; } return count; } public static void Main() { long num = 874512369; Console.WriteLine("Number of" + " digits : " + count_digit(num)); } }
Output
Number of digits : 9