Q. Write a program to print multiplication table of a number.
Given a number n as input our task is to print the multiplication table of a number n.
Multiplication Table:- A list of multiples of a particular number, typically from 1 to 10.
For Example:-
Input : 5
Output :
5 * 1 = 5
5 * 2 = 10
5 * 3 = 15
5 * 4 = 20
5 * 5 = 25
5 * 6 = 30
5 * 7 = 35
5 * 8 = 40
5 * 9 = 45
5 * 10 = 50
Here we can see our input number is 5 and the ouput is the multiplication table of number 5.
Algorithm
START Step 1 : Input number num Step 2 : Loop Start for i = 1; i <= 10; ++i multiply number with i Print the number Loop End STOP
Program To Print Multiplication Table Of A Number
#include <stdio.h> int main() { int num = 5; // Change here to change output for (int i = 1; i <= 10; ++i) printf("%d * %d = %d\n",num,i,num*i); return 0; }
#include <iostream> using namespace std; int main() { int num = 5; // Change here to change output for (int i = 1; i <= 10; ++i) cout << num << " * " << i << " = " << num * i << endl; return 0; }
public class LFC { public static void main(String[] args) { int num = 5; for (int i = 1; i <= 10; ++i) System.out.println(num + " * " + i + " = " + num * i); } }
num = 5 for i in range(1, 11): print(num, 'x', i, '=', num*i)
using System; class LFC { public static void Main() { // Change here to // change output int num = 5; for (int i = 1; i <= 10; ++i) Console.Write(num + " * " + i + " = " + num * i + "\n"); } }
<?php $num = 5; for ($i = 1; $i <= 10; ++$i) echo $num , " * " , $i , " = " , $num * $i , "\n";
#include <stdio.h> int main() { int num = 5; // Change here to change output for (int i = 1; i <= 10; ++i) printf("%d * %d = %d\n",num,i,num*i); return 0; }
Output
5 * 1 = 5 5 * 2 = 10 5 * 3 = 15 5 * 4 = 20 5 * 5 = 25 5 * 6 = 30 5 * 7 = 35 5 * 8 = 40 5 * 9 = 45 5 * 10 = 50
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