Q. Write a program to print all the numbers divisible by 5 or 7 for a given number?

In a given integer N and our task is to print all the numbers less than N, which are divisible by 5 or 7.

For Example :-
Input : 20
Output : 5 7 10 14 15 20

Logic : We have an integer N = 20, now the task is to print all the numbers divisible by 5 and 7 and the limit is 20. For this divide each number from 1 to N by both 5 and 7 and check their remainder. If the remainder is 0 in any of the cases just print that number.

Algorithm

START
Step 1 : Input integer N
Step 2 : Loop Start
            Iterate j from 1 to Num+1
				if j % 5 == 0 || j % 7 == 0
                    print j
		 Loop End
STOP

Program to print all the numbers divisible by 5 or 7

C++

Java

Python

#include <stdio.h>

// Result generator with Num
int NumDiv(int num)
{
 
    // Iterate from 1 to Num+1
    for(int j = 1; j < num + 1; j++)
    {
 
        // Short-circuit operator is used
        if (j % 5 == 0 || j % 7 == 0)
            printf("%d ",j);
    }
    return num;
}
 
int main()
{
    // Input goes here
    int Num = 50;
     
    // Iterating over generator function
    NumDiv(Num);
     
    return 0;
}

#include <bits/stdc++.h>
using namespace std;
 
// Result generator with Num
int NumDiv(int num)
{
 
    // Iterate from 1 to Num+1
    for(int j = 1; j < num + 1; j++)
    {
 
        // Short-circuit operator is used
        if (j % 5 == 0 || j % 7 == 0)
            cout << j << " ";
    }
    return num;
}
 
int main()
{
    // Input goes here
    int Num = 50;
     
    // Iterating over generator function
    NumDiv(Num);
     
    return 0;
}

class LFC{
     
// Result generator with Num
static int NumDiv(int num)
{
 
    // Iterate from 1 to Num+1
    for(int j = 1; j < num + 1; j++)
    {
 
       // Short-circuit operator is used
       if (j % 5 == 0 || j % 7 == 0)
           System.out.print(j + " ");
    }
    return num;
}
 
public static void main(String args[])
{
    // Input goes here
    int Num = 50;
     
    // Iterating over generator function
    NumDiv(Num);
}
}

# Result generator with Num
def NumDiv(num):
     
    # iterate from 1 to Num+1
    for j in range(1, num+1):
 
        # Short-circuit operator is used
        if j % 5 == 0 or j % 7 == 0:
            yield j
 
if __name__ == "__main__":
       
    # input goes here
    Num = 50
 
    # Iterating over generator function
    for j in NumDiv(Num):
        print(j, end = " ")

using System;
class LFC{
     
// Result generator with Num
static int NumDiv(int num)
{
 
    // Iterate from 1 to Num+1
    for(int j = 1; j < num + 1; j++)
    {
 
       // Short-circuit operator is used
       if (j % 5 == 0 || j % 7 == 0)
           Console.Write(j + " ");
    }
    return num;
}
 
// Driver code
public static void Main()
{
 
    // Input goes here
    int Num = 50;
     
    // Iterating over generator
    // function
    NumDiv(Num);
}
}

#include <stdio.h>

// Result generator with Num
int NumDiv(int num)
{
 
    // Iterate from 1 to Num+1
    for(int j = 1; j < num + 1; j++)
    {
 
        // Short-circuit operator is used
        if (j % 5 == 0 || j % 7 == 0)
            printf("%d ",j);
    }
    return num;
}
 
int main()
{
    // Input goes here
    int Num = 50;
     
    // Iterating over generator function
    NumDiv(Num);
     
    return 0;
}

Output

5 7 10 14 15 20 21 25 28 30 35 40 42 45 49 50

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