Q. Program to find length of given string.
String :- The string is defined as an array of characters. The difference between a character array and a string is the string ending with a special character '\0'.
For Eg :- If the string is "hello", the output is 5.
Algorithm to find length of string
START Step 1:Length = 0 Step 2: Repeat step 3 while S1 [Length] ≠ NULL Step 3: Length = Length + 1 Step 4: Return Length STOP
Program to find length of string
#include <stdio.h> #include <string.h> int main() { char a[100]="Letsfindcourse"; int length; for (int i = 0; a[i] != '\0'; i++) lenght += 1; printf("Length of the string = %d\n", length); return 0; }
#include<iostream> using namespace std; int main() { string str = "Letsfindcourse"; // you can also use str.length() cout << "Length of the string = " << str.size(); return 0; }
public class Main { public static void main(String[] args) { //declare the String as an object S1 S2 String S1 = "Letsfindcourse"; //length() method of String returns the length of a String S1. int length = S1.length(); System.out.println("Length of the string = " + length); } }
str1 = "Letsfindcourse" print("Length of the string =",len(str1))
using System; public class LFC { public static void Main() { string str1="Letsfindcourse"; /* Declares a string of size 100 */ int l= 0; foreach(char chr in str1) { l += 1; } Console.Write("Length of the string = {0}\n\n", l); } }
$str1=strlen("Letsfindcourse"); echo "Length of the string = $str1";
#include <stdio.h> #include <string.h> int main() { char a[100]="Letsfindcourse"; int length; length = strlen(a); printf("Length of the string = %d\n", length); return 0; }
Output
Length of the string = 14
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