Q. Write an algorithm and program to check whether the given year is leap year or not.
The article will help you write an algorithm and program to check whether the given year is leap year or not.
Leap year :- A leap year is a calendar year that contains an additional day added to keep the calendar year synchronized. A leap year is exactly divisible by 4, except for the century years (the years ending with 00). Century year is a leap year only if it is completely divisible by 400.
For Example:-
Input = 1999
Output = 1999 is not a leap year
So as we can see that 1999 is not a leap year because 1999 is not divisible by 4.
Here you will find algorithm and program to check whether the given year is leap year or not with explanation.
Leap Year Algorithm
START Step 1 → Initialize variable year Step 3 → Check if year is divisible by 4 but not by 100, DISPLAY "leap year" Step 4 → Check if year is divisible by 400, DISPLAY "leap year" Step 5 → Otherwise, DISPLAY "not leap year" STOP
Leap Year Program
#include <stdio.h>
int main() {
int check_year=1998;
if (check_year % 4 == 0) {
if (check_year % 100 == 0) {
// the check_year is a leap year if it is divisible by 400.
if (check_year % 400 == 0)
printf("%d is a leap year.", check_year);
else
printf("%d is not a leap year.", check_year);
} else
printf("%d is a leap year.", check_year);
} else
printf("%d is not a leap year.", check_year);
return 0;
}
#include <bits/stdc++.h>
using namespace std;
int main()
{
int check_year=1998;
if (check_year % 4 == 0)
{
if (check_year % 100 == 0)
{
if (check_year % 400 == 0)
cout << check_year << " is a leap year.";
else
cout << check_year << " is not a leap year.";
}
else
cout << check_year << " is a leap year.";
}
else
cout << check_year << " is not a leap year.";
return 0;
}
public class Main {
public static void main(String[] args) {
int check_year = 1998;
boolean leap = false;
if(check_year % 4 == 0)
{
if( check_year % 100 == 0)
{
// check_year is divisible by 400, hence the check_year is a leap year
if ( check_year % 400 == 0)
leap = true;
else
leap = false;
}
else
leap = true;
}
else
leap = false;
if(leap)
System.out.println(check_year + " is a leap year.");
else
System.out.println(check_year + " is not a leap year.");
}
}
# Python program to check if year is a leap year or not
check_year = 1998
# To get year (integer input) from the user
# check_year = int(input("Enter a year: "))
if (check_year % 4) == 0:
if (check_year % 100) == 0:
if (check_year % 400) == 0:
print("{0} is a leap year".format(check_year))
else:
print("{0} is not a leap year".format(check_year))
else:
print("{0} is a leap year".format(check_year))
else:
print("{0} is not a leap year".format(check_year))
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace Program
{
class leapyear
{
static void Main(string[] args)
{
leapyear obj = new leapyear();
obj.readdata();
obj.leap();
}
int check_year;
public void readdata()
{
check_year = 1998;
}
public void leap()
{
if ((check_year % 4 == 0 && check_year % 100 != 0) || (check_year % 400 == 0))
{
Console.WriteLine("{0} is a Leap Year", check_year);
}
else
{
Console.WriteLine("{0} is not a Leap Year", check_year);
}
Console.ReadLine();
}
}
}
function isLeap($check_year)
{
return (date('L', mktime(0, 0, 0, 1, 1, $check_year))==1);
}
//For testing
$check_year=1998;
If (isLeap($check_year))
{
echo "$check_year is a Leap Year\n";
}
else
{
echo "$check_year is not a Leap Year\n";
}
#include <stdio.h>
int main() {
int check_year=1998;
if (check_year % 4 == 0) {
if (check_year % 100 == 0) {
// the check_year is a leap year if it is divisible by 400.
if (check_year % 400 == 0)
printf("%d is a leap year.", check_year);
else
printf("%d is not a leap year.", check_year);
} else
printf("%d is a leap year.", check_year);
} else
printf("%d is not a leap year.", check_year);
return 0;
}
Output
1998 is not a leap year.
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