Q. Write an algorithm and program to check harshad (or niven) number.
Program to check Harshad (Or Niven) Number : This section focuses on Harshad Number algorithm and program. This program should be practiced to improve the coding skills required for various interviews (campus interviews, walk-in interviews), coding rounds etc.
Harshad (Or Niven) Number : A harshad number (or Niven number) in a given number base, is an integer that is divisible by the sum of its digits when written in that base. Harshad numbers in base n are also known as n-harshad (or n-Niven) numbers. Here we are given a number n and our task is to check if the number is divisible by sum of digits or not.
For Example :-
Input : n = 18
Output : Yes, The number is Harshad Number
Explanation : As we can see that input number is 18. The sum of digit is 1 + 8 = 9. As, 18 is divisible by 9. So, output for the following code is "Yes, The number is Harshad Number".
Now let us understand what logic we need to use in this :
1. Firstly, we need to extract all the digits from the number using % operator.
2. Calculate the sum of each digit.
3. Check if the number is divisible by sum or not.
Algorithm To Check Harshad Number
\\Algorithm To Check Harshad Number START Step 1 : Initialize sum as 0. Step 2 : Loop begin from n to 0. Calculate -> sum += temp % 10. Step 3 : Divide the original number by sum. Step 4 : Check if divisible by sum or not. Stop
Program To Check Harshad Number
//C Program To Check Harshad Number #include <stdio.h> int main() { int num = 12, sum = 0; //for loop to calculate sum for (int temp = num; temp > 0; temp /= 10) sum += temp % 10; //Check if the number is divisible by sum or not if(num%sum == 0) { printf("Yes, The number is Harshad Number"); } else { printf("No, The number is not Harshad Number"); } return 0; }
//C++ Program To Check Harshad Number #include <iostream> using namespace std; int main() { int num = 12, sum = 0; //for loop to calculate sum for (int temp = num; temp > 0; temp /= 10) sum += temp % 10; //Check if the number is divisible by sum or not if(num%sum == 0) { cout<<"Yes, The number is Harshad Number"; } else { cout<<"No, The number is not Harshad Number"; } return 0; }
//Java Program To Check Harshad Number public class LFC { public static void main(String[] args) { int num = 12, sum = 0; //for loop to calculate sum for (int temp = num; temp > 0; temp /= 10) sum += temp % 10; //Check if the number is divisible by sum or not if(num%sum == 0) { System.out.println("Yes, The number is Harshad Number"); } else { System.out.println("No, The number is not Harshad Number"); } } }
#Python Program To Check Harshad Number num = 12 sum = 0 temp = num #while loop to calculate sum while temp > 0 : sum = sum + temp % 10 temp = temp // 10 #Check if the number is divisible by sum or not if num%sum == 0: print("Yes, The number is Harshad Number") else: print("No, The number is not Harshad Number")
//C# Program To Check Harshad Number using System; class LFC { static void Main() { int num = 12, sum = 0; //for loop to calculate sum for (int temp = num; temp > 0; temp /= 10) sum += temp % 10; //Check if the number is divisible by sum or not if(num%sum == 0) { Console.WriteLine("Yes, The number is Harshad Number"); } else { Console.WriteLine("No, The number is not Harshad Number"); } } }
<?php //PHP Program To Check Harshad Number $num = 12; $sum = 0; $temp = $num; //for loop to calculate sum for ($temp = $num; $temp > 0; $temp /= 10) $sum += $temp % 10; //Check if the number is divisible by sum or not if($num%$sum == 0) echo "Yes, The number is Harshad Number"; else echo"No, The number is not Harshad Number";
//C Program To Check Harshad Number #include <stdio.h> int main() { int num = 12, sum = 0; //for loop to calculate sum for (int temp = num; temp > 0; temp /= 10) sum += temp % 10; //Check if the number is divisible by sum or not if(num%sum == 0) { printf("Yes, The number is Harshad Number"); } else { printf("No, The number is not Harshad Number"); } return 0; }
Output
Yes, The number is Harshad Number
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