## Q. C Program to Count the Number of Digits in a Number.

Here you will find an algorithm and program in C programming language to count number of digits in a number. First let us understand this.

**Explanation : **Suppose an input number is given as 12341 then the output will be 5 as there are 5 digits in the given number and digits are 1, 2, 3, 4, 1.

## Algorithm to count the number of digits in a given number

START step 1 : Declare/Read a number and store it in some variable say num. step 2 : Initialize another variable to store total digits say count = 0. step 3 : If num != 0 then increment count by 1 i.e. count++. step 4 : Divide num by 10 to remove last digit of the given number i.e. num = num / 10. step 5 : Repeat step 3 to 4 till num > 0 or num != 0. STOP

# C Program to Count Number of Digits in a Number

#include <stdio.h> int count_digit(long long num) { int count = 0; while (num != 0) { num = num / 10; ++count; } return count; } int main(void) { long long num = 874512369; printf("Number of digits : %d", count_digit(num)); return 0; }

#### Output

Number of digits : 9