Armstrong Number Program

#include <stdio.h>
int main() {
int num=153, new_num, rem, res = 0;
new_num = num;
while (new_num != 0) {
rem = new_num % 10;
res += rem * rem * rem;
new_num /= 10;
}
if (res == num)
printf("The number %d is an Armstrong number.", num);
else
printf("The number %d is not an Armstrong number.", num);
return 0;
}

#include <iostream>
using namespace std;
int main()
{
int N=153, num, rem, sum = 0;
num = N;
while(num != 0)
{
rem = num % 10;
sum += rem * rem * rem;
num /= 10;
}
if(sum == N)
cout <<"The number "<< N <<" is an Armstrong number.";
else
cout <<"The number "<< N <<" is not an Armstrong number.";
return 0;
}

public class LFC {
public static void main(String[] args) {
int num = 153, new_num, rem, res = 0;
new_num = num;
while (new_num != 0)
{
rem = new_num % 10;
res += Math.pow(rem, 3);
new_num /= 10;
}
if(res == num)
System.out.println("The number "+num+" is an Armstrong number.");
else
System.out.println("The number "+num+" is not an Armstrong number.");
}
}

num = 153
# initialize sum
sum = 0
# find the sum of the cube of each digit
temp = num
while temp > 0:
digit = temp % 10
sum += digit ** 3
temp //= 10
# display the result
if num == sum:
print("The number {0} is Armstrong number".format(num))
else:
print("The number {0} is not Armstrong number".format(num))

using System;  
public class LFC  
{  
public static void Main(string[] args)  
{  
int  n,r,sum=0,temp;           
n= 153;     
temp=n;      
while(n>0)      
{      
r=n%10;      
sum=sum+(r*r*r);      
n=n/10;      
}      
if(temp==sum)      
Console.Write("The number "+temp+" is Armstrong Number.");      
else      
Console.Write("The number "+temp+" is Not Armstrong Number.");      
}  
}  

$num=153;  
$total=0;  
$x=$num;  
while($x!=0)  
{  
$rem=$x%10;  
$total=$total+$rem*$rem*$rem;  
$x=$x/10;  
}  
if($num==$total)  
{  
echo "The number $num is Armstrong number";  
}  
else  
{  
echo "The number $num is not an Armstrong number";  
}